C++旋转点坐标计算

/// 获取A点绕B点旋转P度后的新坐标 /// </summary> /// <param name="Angle">角度</param> /// <param name="CirPoint">圆心坐标</param> /// <param name="MovePoint">移动点的坐标</param> /// <param name="FlagInt">顺时针：1(默认) 逆时针:-1</param> /// <returns></returns> public static Point GetNewPoint(double Angle, Point CirPoint, Point MovePoint, int FlagInt = 1) { //将角度转换成弧度 double Rage2 = Convert.ToDouble(Angle) / 180 * Math.PI; //计算新坐标X int newx = (int)((MovePoint.X - CirPoint.X) * Math.Cos(Rage2 * FlagInt) - (MovePoint.Y - CirPoint.Y) * Math.Sin(Rage2 * FlagInt)); //计算新坐标Y int newy = (int)((MovePoint.Y - CirPoint.Y) * Math.Cos(Rage2 * FlagInt) + (MovePoint.X - CirPoint.X) * Math.Sin(Rage2 * FlagInt)); //计算新坐标 Point newpoint = new Point(CirPoint.X + newx, CirPoint.Y + newy); //返回新坐标 return newpoint; }

创作不易，小小的支持一下吧！